相対 Special Relativity · Simulation

Addition of Relativistic Velocity & Spacetime Invariance

Aim: to investigate Einstein's relativistic velocity addition theorem in Special Relativity, demonstrate why no physical object can exceed \(c\), observe the invariance of the speed of light under Lorentz boosts, and visualize worldlines on a Minkowski spacetime diagram.

Twin Reference Frames & Relativistic Flight

Frame S (Lab) vs Frame S' (Cruiser)
Watch the scout probe fire from Cruiser A. Even when both travel at 0.90c, their combined speed from Earth remains strictly < c.

Spacetime Minkowski Diagram (\(ct\) vs \(x\))

Einstein vs. Galilean Velocity Addition

Relativistic Transformation Catalog

Derivation from the Lorentz Transformation

Consider two inertial frames: \(S\) (Earth base station) and \(S'\) (Cruiser spacecraft) moving along the common \(x\)-axis at velocity \(v\). The coordinates transform via the Lorentz transformation:

$$ x' = \gamma (x - v t), \qquad t' = \gamma \left(t - \frac{v x}{c^2}\right) $$

Taking differentials \(dx'\) and \(dt'\):

$$ dx' = \gamma (dx - v dt), \qquad dt' = \gamma \left(dt - \frac{v dx}{c^2}\right) $$

Dividing \(dx'\) by \(dt'\) gives the velocity in \(S'\):

$$ u' = \frac{dx'}{dt'} = \frac{\gamma(dx - v dt)}{\gamma(dt - v dx/c^2)} = \frac{\frac{dx}{dt} - v}{1 - \frac{v}{c^2}\frac{dx}{dt}} = \frac{u - v}{1 - \frac{u v}{c^2}} $$

Inverting to solve for the velocity \(u\) as observed from frame \(S\):

$$ u = \frac{u' + v}{1 + \frac{u' v}{c^2}} $$

In the Newtonian limit (\(u', v \ll c\)), the denominator \(1 + \frac{u'v}{c^2} \to 1\), recovering Galileo's addition formula \(u = u' + v\).

Invariance of the Speed of Light & Light Cone

If the probe is a light pulse or photon (\(u' = c\)):

$$ u = \frac{c + v}{1 + \frac{c v}{c^2}} = \frac{c(1 + v/c)}{1 + v/c} = c $$

The speed of light is identical in every inertial frame, fulfilling Einstein's Second Postulate. Furthermore, if \(u' < c\) and \(v < c\), their composition is strictly bounded:

$$ c - u = \frac{c(1 - u'/c)(1 - v/c)}{1 + \frac{u' v}{c^2}} > 0 \implies u < c $$

No combination of sub-luminal velocities can ever reach or breach the light speed barrier.

Viva Questions

What is the Lorentz factor \(\gamma\) and how does it behave as \(u \to c\)?

\(\gamma = 1/\sqrt{1 - u^2/c^2}\). At rest (\(u=0\)), \(\gamma = 1\). As \(u \to c\), \(\gamma \to \infty\), demanding infinite energy to accelerate a massive particle to the speed of light.

What causes the tilt in the simultaneity axis \(x'\) on the Minkowski diagram?

The time transformation \(t' = \gamma(t - vx/c^2)\). Events simultaneous in \(S'\) (\(t' = 0\)) satisfy \(t = (v/c^2)x\), forming a tilted line of slope \(v/c\) in the \((x, ct)\) plane.